Question

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The electric field in the region is given by: $E=(i^20+j^ 30)N/C$

The position of the point is at $(2m,2m)$

The displacement vcector for the point is $r=(2i+2j)$

Therefore, the potential at the point is:

So, $V=−E×r$

$=−(i20+30J)(2i^+2j)$

$=−(2×20+2×30)=−100V$.

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