In ΔABC right angled at B, AB = 24 cm, BC = 7 m. Determine sin C, cos C

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#### Solution

Applying Pythagoras theorem for ΔABC, we obtain

AC^{2} = AB^{2} + BC^{2}

= (24 cm)^{2} + (7 cm)^{2}

= (576 + 49) cm^{2}

= 625 cm^{2}

∴ AC =`sqrt(625)` cm = 25 cm

sin C =`(`

cos C =`(`

Concept: Trigonometric Ratios

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